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Home/ Questions/Q 1000653
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T07:32:52+00:00 2026-05-16T07:32:52+00:00

I have a Java program with code: public class Test1 { public static void

  • 0

I have a Java program with code:

public class Test1 {
public static void main(String args[]) throws InterruptedException,
        IOException {
    String cmd = "cmd /c start test.bat";
    Process p = Runtime.getRuntime().exec(cmd); 
    InputStream stderr = process.getErrorStream();
    InputStreamReader isr = new InputStreamReader(stderr);
    BufferedReader br = new BufferedReader(isr);
    String line = null;

    while ((line = br.readLine()) != null){
        System.out.println(line);}

      p.waitFor(); 
      int exitVal = p.exitValue(); 
      System.out.println(exitVal);

}
}

test.bat executes another program which has the folowing code:

public class ConnectionTest {

public Connection getConn throws SQLException{
      Connection conn = null;
      Statement st = null;
      ResultSet rs = null;
      String driverName = "com.ibm.db2.jcc.DB2Driver22222";
        try {
                Class.forName(driverName).newInstance();
            } catch (Exception e) {
                e.printStackTrace();

                System.exit(1);
                                } 

;;;;
;;;;
;;;
;;;

But from the Test1, the exit value is always 0. HOw come, when the batch is executed, it will run the
ConnectionTest class and it will get exception as it will not find DB2Driver22222.

Can anybody explain to me why I am not getting correct error code nor any error messages.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T07:32:52+00:00Added an answer on May 16, 2026 at 7:32 am

    The problem is that you are recieving the return code of the start command, and not what the start command executes. Though start may see test.bat exit with code 1, start itself exits success (0). Execute the .bat directly instead:

    String cmd = "test.bat";
    
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