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Home/ Questions/Q 787229
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T21:10:08+00:00 2026-05-14T21:10:08+00:00

I have a Java Thread which exposes a property which other threads want to

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I have a Java Thread which exposes a property which other threads want to access:

class MyThread extends Thread {
   private Foo foo;
   ...
   Foo getFoo() {
     return foo;
   }
   ...
   public void run() { 
     ...
     foo = makeTheFoo();
     ...
   }
}

The problem is that it takes some short time from the time this runs until foo is available. Callers may call getFoo() before this and get a null. I’d rather they simply block, wait, and get the value once initialization has occurred. (foo is never changed afterwards.) It will be a matter of milliseconds until it’s ready, so I’m comfortable with this approach.

Now, I can make this happen with wait() and notifyAll() and there’s a 95% chance I’ll do it right. But I’m wondering how you all would do it; is there a primitive in java.util.concurrent that would do this, that I’ve missed?

Or, how would you structure it? Yes, make foo volatile. Yes, synchronize on an internal lock Object and put the check in a while loop until it’s not null. Am I missing anything?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T21:10:09+00:00Added an answer on May 14, 2026 at 9:10 pm

    If foo is initialized only one time, a CountDownLatch is a great fit.

    class MyThread extends Thread {
    
      private final CountDownLatch latch = new CountDownLatch(1);
    
      ...
    
      Foo getFoo() throws InterruptedException
      {
        latch.await(); /* Or use overload with timeout parameter. */
        return foo;
      }
    
      @Override
      public void run() {
        foo = makeTheFoo()
        latch.countDown();
      }
    
    }
    

    Latches provide the same visibility behavior as the volatile keyword, meaning that reading threads will see the value of foo assigned by the thread, even though foo isn’t declared volatile.

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