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Home/ Questions/Q 868901
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T10:13:14+00:00 2026-05-15T10:13:14+00:00

I have a javascript array containing the name and values of radios I want

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I have a javascript array containing the name and values of radios I want checked.

jQuery(window).load(function(){

var selected_options = new Array();
selected_options['swing_type'] = 'Slide';

    var x;
    for (x in selected_options){
        jQuery("#menu input[name="+ x +"][value="+ selected_options[x] +"]").attr('checked', 'checked');
    }
});

And the html has something like:

<td>
    <input type="radio" id="swing" name="swing_type" value="Swing" /><label for="swing"> Swing</label><br />

    <input type="radio" id="slide" name="swing_type" value="Slide" /><label for="slide"> Slide</label>
  </td>

When I run this script, the browser becomes unresponsive. I’ve tried a few variations, the following two worked:

 jQuery("#menu input[value="+ selected_options[x] +"]").attr('checked', 'checked'); 
jQuery("#menu input[name=swing_type][value=Swing]").attr('checked', 'checked');

The following did not work:

jQuery("#menu input[name=swing_type][value="+ selected_options[x] +"]").attr('checked', 'checked');

I’m hoping someone can enlighten me to what is wrong. I want to target the correct radio inputs. If I only target the values, I could see a case where there could be two separate sets with Yes/No values. Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T10:13:15+00:00Added an answer on May 15, 2026 at 10:13 am

    You’re doing a for/in over an Array. This can sometimes cause problems.

    Since you are specifying named keys, you should use an object instead:

    var selected_options = {};
    

    or

    var selected_options = new Object();
    

    Test the example: http://jsfiddle.net/Ds3s8/

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