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Home/ Questions/Q 8632401
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T09:20:51+00:00 2026-06-12T09:20:51+00:00

I have a job application form returning a person’s details among other things. Right

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I have a job application form returning a person’s details among other things.

Right now, these are returned on separate lines. And if there are no entries in any field, there is a blank line in the email that is sent.

I’d like to make an IF statement so that if there is no entry in any field, it will return “Not Applicable” in the mail.

example:

$nrel1 = $_POST['nrel1'];
$nrel11_name = $_POST['nrel1_name'];
$nrel1_age = $_POST['nrel1_age'];
$nrel1_gender = $_POST['nrel1_gender'];
$nrel1_education = $_POST['nrel1_education'];
$nrel2_employment = $_POST['nrel2_employment'];

Now if the applicant makes no entry in the $nrel1_age field, I want it to return “Not Applicable” in the mail.

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  1. Editorial Team
    Editorial Team
    2026-06-12T09:20:51+00:00Added an answer on June 12, 2026 at 9:20 am
    function valueOrNotApplicable($array, $key)
    {
        if (isset($array[$key]) && !empty($array[$key]))
            return $array[$key];
        else
            return 'Not Applicable';
    }
    
    $nrel1            = valueOrNotApplicable($_POST, 'nrel1');
    $nrel11_name      = valueOrNotApplicable($_POST, 'nrel1_name');
    $nrel1_age        = valueOrNotApplicable($_POST, 'nrel1_age');
    $nrel1_gender     = valueOrNotApplicable($_POST, 'nrel1_gender');
    $nrel1_education  = valueOrNotApplicable($_POST, 'nrel1_education');
    $nrel2_employment = valueOrNotApplicable($_POST, 'nrel2_employment');
    

    It’s good to check both isset() and !empty(). If you don’t check for isset() then you may get “PHP Notice: Undefined index” warnings.

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