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Home/ Questions/Q 6637169
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T23:16:48+00:00 2026-05-25T23:16:48+00:00

I have a JPanel that contains a JScrollPane that contains a JTable. Inside my

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I have a JPanel that contains a JScrollPane that contains a JTable. Inside my panel constructor it’s created this way:

    //inside MyPanel extends JPanel class constructor
public void MyPanel(){
    TitledBorder border = BorderFactory.createTitledBorder("title");
    this.setLayout(new BoxLayout(this, BoxLayout.Y_AXIS));
    this.scrollTable = new JScrollPane(table);
    this.scrollTable.setBorder(border);
}

Now, the user should be able to load another table into application so I need to remove the previous one from the scrollpane and add a new one.
I’ve tried the following :

public void setNewTable(JTable t ) {
    this.scrollTable.removeAll();
    this.scrollTable.add(t);
    this.scrollTable.validate();

}

The previous table is removed, but nothing happear inside the JScrollPane now.

What am I doing wrong?

public void

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  1. Editorial Team
    Editorial Team
    2026-05-25T23:16:48+00:00Added an answer on May 25, 2026 at 11:16 pm

    You can’t just add to JScrollPane, since it consists of other internal components.

    From the JavaDocs:

    enter image description here

    By calling scrollPane.removeAll() you essentially, remove the header, view, and scrollbars, and add a component that the scrollpane doesn’t understand.

    First of all, you generally shouldn’t pass around tables in that manner. It would be much better to instead pass in a TableModel, and change the model on the table via JTable.setModel().

    That said, if you absolutely want to pass in a table, you need to set the view on the viewport in the scrollpane:

    scrollPane.getViewport().setView(table)
    
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