Question

I have a jquery function which relies on an array of images to create a fadeOut/In effect.

The line of code looks like this:

var images=new Array('/images/myImage1.jpg','/images/myImage2.jpg','/images/myImage3.jpg');

Currently I manually create this array but I would like to create it using php to grab the images in a directory on my server. I have found the following code which does this but I need to format so it looks like the javascript above.

<?php
$dir    = 'chamberImages/portfolio';
$files2 = scandir($dir, 1);
print_r($files2);
?>

Answer 1

You could just JSON encode the array that you have in $files2, removing the . and .. entries with array_slice:

var images = <?php echo json_encode(array_slice($files2, 2)); ?>;