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Home/ Questions/Q 6055671
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T08:17:26+00:00 2026-05-23T08:17:26+00:00

I have a jQuery/Javascript search script which includes a tabbed search box. Currently, there

  • 0

I have a jQuery/Javascript search script which includes a tabbed search box. Currently, there are lines in my code which are completely unnecessary. How can I simplify all of my code which I have pasted below.

My HTML code:

<div id='nav'>
<ul>
<li><a href='javascript:void(null);' class='type search'>Web</a></li>
<li><a href='javascript:void(null);' class='type images'>Images</a></li>
<li><a href='javascript:void(null);' class='type videos'>Videos</a></li>
<li><a href='javascript:void(null);' class='type news'>News</a></li>
<li><a href='javascript:void(null);' class='type social'>Social</a></li>
</ul>
</div>

<form id='search' method='post'>
<input type='text' id='query'>
</form>
<div id="results"></div>

My jQuery/Javascript code:

$(document).ready(function () {
    Tabs.types.init('search');
    Tabs.search.init();
});

var Tabs = {
    search: {
        init: function () {
            jQuery(Tabs.element.form).bind('submit', function (evt) {
                evt.preventDefault();
            });
        },
        submit: function () {
                var type = Tabs.types.selected;
        },
    },
    types: {
        init: function (selected) {
            Tabs.types.selected = selected;
            jQuery('.' + Tabs.types.selected).addClass('selected');
            jQuery(Tabs.element.types).bind('click', function () {
                Tabs.types.click(jQuery(this));
            });
        },
        click: function (obj) {
            jQuery(Tabs.element.types).each(function () {
                if (jQuery(this).hasClass('selected')) {
                    jQuery(this).removeClass('selected');
                }
            });
            if (obj.hasClass('web')) Tabs.types.selected = 'search';
            if (obj.hasClass('images')) Tabs.types.selected = 'images';
            if (obj.hasClass('videos')) Tabs.types.selected = 'videos';
            if (obj.hasClass('news')) Tabs.types.selected = 'news';
            if (obj.hasClass('social')) Tabs.types.selected = 'social';
            obj.addClass('selected');
        }
    },
    element: {
        types: '.type',
        form: '#search',
    },
};

$(document).ready(function(){
    $("#query").keyup(function(e){
        if(e.keyCode==13){
            var query=$(this).val();
            var yt_url=''+Tabs.types.selected+'.php?q='+query;
            window.location.hash=''+Tabs.types.selected+'/'+query+'/';
            $.ajax({
                type:"GET",
                url:yt_url,
                dataType:"html",
                success:function(results){
                   $('#results').html(results);
                }
            });
        }
    });
});
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T08:17:27+00:00Added an answer on May 23, 2026 at 8:17 am

    for example,
    you can unify css classes and types so you can write just Typs.types.selected = obj.class

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