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Home/ Questions/Q 6667059
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T02:53:37+00:00 2026-05-26T02:53:37+00:00

I have a jquery script, where if you mouseenter and element, something shows, and

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I have a jquery script, where if you mouseenter and element, something shows, and disappears when you mouseleave. I’m trying to unbind the mouseleave when user clicks, so that “something” stays showing when user leaves. Is this the correct way to do it? If so, can someone help me get this script to work?

Thank you!

$('.block').live("mouseenter",function(){
        var id= $(this).attr('id');
        $('#arrowPreview'+id).show();


    }).live("mouseleave",function(){
        var id= $(this).attr('id');
        $('#arrowPreview'+id).hide();

    }).live("click",function(){
        var id= $(this).attr('id');
        $('#arrowPreview'+id).show();
        $(this).unbind("mouseleave");
    });

Thank you!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T02:53:37+00:00Added an answer on May 26, 2026 at 2:53 am

    So I don’t think what you want is exactly possible. The problem appears to be the use of .live and unbind. You can unbind the mouseleave event with .die. However, the selector used must match the one originally used to bind the event, in your case .block. I am thinking that this obviously is bad. Example Fiddle of .die

    http://jsfiddle.net/EZNDg/

    I think that instead you need to bind using an explicit selector for the current element, so perhaps using .each with your selector and then binding with $(this). This should allow die to work. I will mess with this Fiddle and see if it is true.

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