Question

i have a jquery script, which posts my form. here it is:

$(document).ready(function(){
$("form#submit").submit(function() {


var an      = $('#an').attr('value');
var betreff = $('#betreff').attr('value');
var text    = $('#text').attr('value');

    $.ajax({
        type: "POST",
        url: "newmsg.php",
        data: "an="+ an +"& betreff="+ betreff +"&text="+ text,
        success: function(){

            $('#window').html(name);                

        }
    });
return false;
});
});

my newmsg.php file

<?php if($_POST['an']=="john") { echo json_encode(array("name"=>"hi john")); } ?>

my problem is, that my php file will not return the name, so my div #window does not post the message

hope you guys understand…

thank you very much

Answer 1

Try

success: function(data){
    var json = $.parseJSON(data);
    $('#window').html(json.name);                
}