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Home/ Questions/Q 6845117
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T00:27:39+00:00 2026-05-27T00:27:39+00:00

I have a js in a folder js. I call the file in the

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I have a js in a folder js. I call the file in the header.
I have the next code in my view:

<?php echo form_dropdown('mydropdown',$options) ?>

I need to pass the paramether $js, could you help me with the syntax?

$js = 'id="shirts" onChange="display(this,\'id1\',\'id2\');"';


<?php echo form_dropdown('mydropdown',$options, $js) ?>

When I see the source code of my dropdown I can’t see the id=”shirts”, then I believe that the function javascript is not recognized.

What’s my error. My codeigniter version is 2.0.

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-27T00:27:40+00:00Added an answer on May 27, 2026 at 12:27 am

    javascript should be the fourth parameter to this call. So add a null parameter in the third (which is for the selected value of the dropdown):

    <?php echo form_dropdown('mydropdown',$options, null, $js) ?>
    

    http://ellislab.com/codeigniter/user_guide/helpers/form_helper.html

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