Question

I have a JSF converter that I use for a SelectItem list containing several different entity types. In the getAsString() method I create the string as the class name suffixed with “:” and the ID.

MySuperClass superClass = (MySuperClass)value;
if(superClass != null) {
  return String.valueOf(superClass.getClass().getName()+":"+superClass.getId());
}

This allows me to load the correct entity in the getAsObject() on the way back from the UI by doing this :

String className = value.substring(0, value.indexOf(":"));
long id = Long.parseLong(value.substring(value.indexOf(":")+1));
Class<T> entitySuperClass = (Class<T>) Class.forName(className);
MySuperClass superClass = (MySuperClass)getEntityManager().find(entitySuperClass, id);

My problem is that my entity in getAsString() is a proxy. So instead of getting com.company.MyEntity when I do a getClass().getName() I am getting com.company.MyEntity_$$_javassist_48 so then it fails on the find().

Is there any way (aside from String manipulation) to get the concrete class name (eg. com.company.MyEntity)?

Thanks.

Answer 1

Instead of superClass.getClass() try org.hibernate.proxy.HibernateProxyHelper.getClassWithoutInitializingProxy(superClass).