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Home/ Questions/Q 6248207
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T13:00:52+00:00 2026-05-24T13:00:52+00:00

I have a JSON array like this: _htaItems = [ {ID:1, parentColumnSortID:0, description:Precondition, columnSortID:1,

  • 0

I have a JSON array like this:

_htaItems = [
    {"ID":1,
     "parentColumnSortID":"0",
     "description":"Precondition",
     "columnSortID":"1",
     "itemType":0},
    {"ID":2,
     "parentColumnSortID":"0",
     "description":"Precondition",
     "columnSortID":"1",
    "itemType":0}]

I want to update this by passing the ID, column name and new value to a function:

    function updateJSON(ID, columnName, newValue)
    {
        var i = 0;
        for (i = 0; i < _htaItems.length; i++)
        {
            if (_htaItems[i].ID == ID)
            {
                ?????
            }
        }
    }  

My question is, how do I update the value? I know I can do something like the following:

 _htaItems[x].description = 'New Value'

But in my cause, the column name is being passed as a string.

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  1. Editorial Team
    Editorial Team
    2026-05-24T13:00:53+00:00Added an answer on May 24, 2026 at 1:00 pm

    In JavaScript, you can access an object property either with literal notation:

    the.answer = 42;
    

    Or with bracketed notation using a string for the property name:

    the["answer"] = 42;
    

    Those two statements do exactly the same thing, but in the case of the second one, since what goes in the brackets is a string, it can be any expression that resolves to a string (or can be coerced to one). So all of these do the same thing:

    x = "answer";
    the[x] = 42;
    
    x = "ans";
    y = "wer";
    the[x + y] = 42;
    
    function foo() {
        return "answer";
    }
    the[foo()] = 42;
    

    …which is to set the answer property of the object the to 42.

    So if description in your example can’t be a literal because it’s being passed to you from somewhere else, you can use bracketed notation:

    s = "description";
    _htaItems[x][s] = 'New Value';
    
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