Question

I have a JSON file with 2 JSON-Arrays in it:
One Array for routes and one Array for sights.

A route should consist of several sights where the user gets navigated to.
Unfortunately I am getting the error:

JSONException: Value of type java.lang.String cannot be converted to JSONObject

Here are my variables and the code that parses the JSON-File:

private InputStream is = null;
private String json = "";
private JSONObject jObj = null;

try {
    BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
    StringBuilder sb = new StringBuilder();
    String line = null;
    while ((line = reader.readLine()) != null) {
        sb.append(line + "\n");
    }
    is.close();
    // hier habe ich das JSON-File als String
    json = sb.toString();
    Log.i("JSON Parser", json);
} catch (Exception e) {
    Log.e("Buffer Error", "Error converting result " + e.toString());
}

// try parse the string to a JSON object
try {
    jObj = new JSONObject(json);
} catch (JSONException e) {
    Log.e("JSON Parser", "Error parsing data " + e.toString());
}

// return JSON String
return jObj;
}

Log.i(“JSON Parser”, json);
shows me that at the beginning of the generated string there is a strange sign:

but the error happens here:

try {
    jObj = new JSONObject(json);
} catch (JSONException e) {
    Log.e("JSON Parser", "Error parsing data " + e.toString());
}

04-22 14:01:05.043: E/JSON Parser(5868): Error parsing data
org.json.JSONException: Value //STRANGE SIGN HERE // of type
java.lang.String cannot be converted to JSONObject

anybody has a clue on how to get rid of these signs in order to create the JSONObject?

Answer 1

see this
http://stleary.github.io/JSON-java/org/json/JSONObject.html#JSONObject-java.lang.String-

JSONObject

public JSONObject(java.lang.String source)
           throws JSONException

Construct a JSONObject from a source JSON text string. This is the most commonly used` JSONObject constructor.

Parameters:
    source - `A string beginning with { (left brace) and ending with } (right brace).` 
Throws:
    JSONException - If there is a syntax error in the source string or a duplicated key.

you try to use some thing like:

new JSONObject("{your string}")