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Home/ Questions/Q 6843105
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T00:12:21+00:00 2026-05-27T00:12:21+00:00

I have a json structure that I’m decoding that looks like this: person =>

  • 0

I have a json structure that I’m decoding that looks like this:

  person => {
    city => "Chicago",
    id => 123,
    name => "Joe Smith",
    pets => {
      cats => [
                { age => 6, name => "cat1", type => "siamese", weight => "10 kilos" },
                { age => 10, name => "cat2", type => "siamese", weight => "13 kilos" },
              ],
      dogs => [
                { age => 7, name => "dog1", type => "siamese", weight => "20 kilos" },
                { age => 5, name => "dog2", type => "siamese", weight => "15 kilos" },
              ],
    },
  },
}

I’m able to print the city, id, name by doing:

foreach my $listing ($decoded->{person})
{ 
    my $city = $listing->{city};
    my $name = $listing->{name};
    name - $city - \n";
}

however, I’m unsure of how to print the pets->cats or pets->dogs. I’m able to do a dump of them by:

my @pets = $listing->{pets}->{cats};
dump @pets;

but I’m not sure how to access them through the hash structure.

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  1. Editorial Team
    Editorial Team
    2026-05-27T00:12:22+00:00Added an answer on May 27, 2026 at 12:12 am

    Assuming your $listing is a person you have to dereference array and hash refs.

    # as long as we are assuming $listing is a person
    # this goes inside the foreach you posted in your
    # question.
    
    # this will print all cats' names
    foreach my $cat ( @{ $listing->{pets}->{cats} } )
    {
        # here $cat is a hash reference
    
        say $cat->{name}; # cat's name
    }
    

    and so on for other stuff.

    To access them from the structure you can do:

    say $listing->{pets}->{cats}->[0]->{name}; # this will print 'cat1'
    
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