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Home/ Questions/Q 6575785
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T15:25:49+00:00 2026-05-25T15:25:49+00:00

I have a large block of HTML that needs to be replaced, which includes

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I have a large block of HTML that needs to be replaced, which includes fadeOut/fadeIn transitions. I can’t figure out how to add the HTML to the page (hidden) without wrapping it in a div.

$.get('/ajax', function(newHtml){
    var $newEvent = $('<div class="new-event" />').hide().html(newHtml);
    $('#content .event').fadeOut('slow', function(){
        $(this).remove(); //old event
        $newEvent.appendTo('#content').fadeIn('slow').removeClass('new-event'); //then remove the wrapper div that I didnt need in the first place
    });
});

What is the best way to do this while utilizing best practices for performance?

Solution:

For some reason, I thought that creating a new element like this: $(newHtml) was less efficient (bad performance) than html(newHtml). But apparently, they are the same as far as performance goes (I have no data to back this up other than my own observations).

So the following code is just as efficient as the previous:

$.get('/ajax', function(newHtml){
    var $newEvent = $(newHtml).hide();
    $('#content .event').fadeOut('slow', function(){
        $(this).remove(); //old event
        $newEvent.appendTo('#content').fadeIn('slow');
    });
});
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  1. Editorial Team
    Editorial Team
    2026-05-25T15:25:50+00:00Added an answer on May 25, 2026 at 3:25 pm

    When adding the code to the page, have top level elements all be hidden

    <div style="display:none;">...</div>
    

    When fadeIn is called jQuery automatically removes it for you.

    If you can’t modify the returned html just do it this way then,

    $(newHtml).hide().appendTo('#content');
    

    That will hide it before being added to the DOM.

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