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Home/ Questions/Q 6815791
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T20:50:56+00:00 2026-05-26T20:50:56+00:00

I have a layout in XML as follows: <LinearLayout android:layout_width=fill_parent android:layout_height=fill_parent android:onClick=myButton.performClick /> myButton

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I have a layout in XML as follows:

<LinearLayout
            android:layout_width="fill_parent"
            android:layout_height="fill_parent"
            android:onClick="myButton.performClick" />

myButton is a member of this activity, is it possible use a class member method here?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T20:50:57+00:00Added an answer on May 26, 2026 at 8:50 pm

    No, as the docs say (emphasis mine):

    you must declare a public void sayHello(View v) method of your context
    (typically, your Activity)

    If you wanted to execute a method on a field, you could wrap it I suppose.

    <LinearLayout
            android:layout_width="fill_parent"
            android:layout_height="fill_parent"
            android:onClick="performClick" />
    

    Then:

    public void performClick(View view) {
        myButton.performClick(view);
    }
    

    but that almost defeats the purpose of the XML onClick attribute (making things more concise). Is there a good reason for performClick to be on your button instead of your activity anyway?

    Lastly, doing this on the LinearLayout is fine. The attribute is supported for all Views.

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