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Asked: 2026-05-11T03:56:14+00:00

I have a legacy MySQL table called lnk_lists_addresses with columns list_id and address_id .

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I have a legacy MySQL table called lnk_lists_addresses with columns list_id and address_id. I’d like to write a query that reports all the cases where the same list_id–address_id combination appears more than once in the table with a count.

I tried this…

SELECT count(*), list_id, address_id FROM lnk_lists_addresses GROUP BY list_id, address_id ORDER BY count(*) DESC LIMIT 20

It works, sort of, because there are fewer than 20 duplicates. But how would I return only the counts greater than 1?

I tried adding ‘WHERE count(*) > 1‘ before and after GROUP BY but got errors saying the statement was invalid.

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1 Answer

  1. SELECT count(*), list_id, address_id FROM lnk_lists_addresses GROUP BY list_id, address_id HAVING count(*)>1 ORDER BY count(*) DESC

    To combine mine and Todd.Run’s answers for a more ‘complete’ answer. You want to use the HAVING clause:

    http://dev.mysql.com/doc/refman/5.1/en/select.html

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