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Home/ Questions/Q 504481
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:30:05+00:00 2026-05-13T06:30:05+00:00

I have a lib directory in my applications main directory, which contains an arbitrary

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I have a “lib” directory in my applications main directory, which contains an arbitrary number of subdirectories, each having its own Makefile.

I would like to have a single Makefile in the main directory, that calls each subdirectory’s Makefile. I know this is possible if I manually list the subdirs, but I would like to have it done automatically.

I was thinking of something like the following, but it obviously does not work. Note that I also have clean, test, etc. targets, so % is probably not a good idea at all.

LIBS=lib/*

all: $(LIBS)

%:
  (cd $@; $(MAKE))

Any help is appreciated!

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:30:05+00:00Added an answer on May 13, 2026 at 6:30 am

    The following will work with GNU make:

    LIBS=$(wildcard lib/*)
    all: $(LIBS)
    .PHONY: force
    $(LIBS): force
      cd $@ && pwd
    

    If there might be something other than directories in lib, you could alternatively use:

    LIBS=$(shell find lib -type d)
    

    To address the multiple targets issue, you can build special targets for each directory, then strip off the prefix for the sub-build:

    LIBS=$(wildcard lib/*)
    clean_LIBS=$(addprefix clean_,$(LIBS))
    all: $(LIBS)
    clean: $(clean_LIBS)
    .PHONY: force
    $(LIBS): force
      echo make -C $@
    $(clean_LIBS): force
      echo make -C $(patsubst clean_%,%,$@) clean
    
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