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Home/ Questions/Q 7007947
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T21:40:22+00:00 2026-05-27T21:40:22+00:00

I have a likely simple problem that I need help with. I have two

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I have a likely simple problem that I need help with.

I have two js files that I have loaded on a page via tag in html. All the code in both these files is executed / loaded within $(document).ready();

On a certain event, function A defined in the first file tries to call function B defined in the other file. However, this fails, I get an error that function B is not defined.

I notice that if I take the definition of function B outside of $(document).ready(), that function A is able to call function B – it is in scope.

Why?

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  1. Editorial Team
    Editorial Team
    2026-05-27T21:40:23+00:00Added an answer on May 27, 2026 at 9:40 pm

    It is a scope issue. Everything defined within a function is accessible only within that function unless made global in some other way. When you move the function outside of the ready function it becomes global making it accessible globally.

    EDIT: When I say “made global in some other way”, I mean something like this:

    window.something = "something";
    

    This will create a global variable something even if this line of code exists within your ready function.

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