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Home/ Questions/Q 48931
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Asked: May 10, 20262026-05-10T16:21:26+00:00 2026-05-10T16:21:26+00:00

I have a line that I draw in a window and I let the

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I have a line that I draw in a window and I let the user drag it around. So, my line is defined by two points: (x1,y1) and (x2,y2). But now I would like to draw ‘caps’ at the end of my line, that is, short perpendicular lines at each of my end points. The caps should be N pixels in length.

Thus, to draw my ‘cap’ line at end point (x1,y1), I need to find two points that form a perpendicular line and where each of its points are N/2 pixels away from the point (x1,y1).

So how do you calculate a point (x3,y3) given it needs to be at a perpendicular distance N/2 away from the end point (x1,y1) of a known line, i.e. the line defined by (x1,y1) and (x2,y2)?

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  1. 2026-05-10T16:21:27+00:00Added an answer on May 10, 2026 at 4:21 pm

    You need to compute a unit vector that’s perpendicular to the line segment. Avoid computing the slope because that can lead to divide by zero errors.

    dx = x1-x2 dy = y1-y2 dist = sqrt(dx*dx + dy*dy) dx /= dist dy /= dist x3 = x1 + (N/2)*dy y3 = y1 - (N/2)*dx x4 = x1 - (N/2)*dy y4 = y1 + (N/2)*dx 
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