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Home/ Questions/Q 8014341
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T19:54:14+00:00 2026-06-04T19:54:14+00:00

I have a linear layout <LinearLayout xmlns:android=http://schemas.android.com/apk/res/android android:id=@+id/layout_menu android:layout_width=fill_parent android:layout_height=70px android:layout_alignParentBottom=true android:background=@drawable/footer_bar android:gravity=center >

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I have a linear layout

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/layout_menu"
android:layout_width="fill_parent"
android:layout_height="70px"
android:layout_alignParentBottom="true"
android:background="@drawable/footer_bar"
android:gravity="center" >
</LinearLayout>

When i set condition

if (constant.getscreenresolution() >= 800) {
    //i want to make it height * 2
}

So how to set the layout params?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T19:54:16+00:00Added an answer on June 4, 2026 at 7:54 pm

    hope this helps you

    LinearLayout.LayoutParams layout_param= new LinearLayout.LayoutParams(
                    LinearLayout.LayoutParams.fill_parent,
                    height * 2);
    mLayout = (LinearLayout) findViewById(R.id.layout_menu);
    mLayout.setLayoutParams(layout_param);
    
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