Question

I have a link that looks like

<a class="fancy" href="/site/feedback">feedback</a>

Ajax call:

$('.fancy').fancybox({
    wrapCSS: 'custom-fancy',
    padding: 0,
    type: 'ajax'
});

On click fancybox load content wich controller send.

$this->renderPartial('_feedback')

Feedback view:

<?php
/* @var $this Controller */
/* @var $model FeedbackForm */
/* @var $form CActiveForm */

$form = $this->beginWidget('CActiveForm', array(
    'id' => 'feedback-form',
    'enableClientValidation' => TRUE,
)); ?>
<div><?= $form->textArea($model, 'feedback') ?></div>
<?=$form->error($model, 'feedback')?>
<? $this->widget('CCaptcha') ?>
<?=$form->textField($model, 'verifyCode', array('placeholder' => 'Captcha code'))?>
<div><?=CHtml::submitButton('Send', array('class' => 'r button'))?></div>
<? $this->endWidget() ?>

The problem is that there is no javascript/ajax validation on this loaded form. I think, it is because some Yii scripts did not loaded after ajax call (yiiActiveForm.js maybe, I don’t know).
What is the best solution for this situation?

Answer 1

Well, you need to load some code with javascript

$output = $this->renderPartial('_feedback', array(), true)
// you need set layout to false for render only your form
Yii::app()->clientScript->render($output);
// where you need remove jquery for prevent double initiation's jquery script
// it's not worked example!!!
preg_replace('@<script type="text/javascript" src="jquery.js"></script>@mi', '', $output);
// well, we may output
echo $output;