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Home/ Questions/Q 7960317
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T04:43:17+00:00 2026-06-04T04:43:17+00:00

I have a linked list, and I want to sort them by names (for

  • 0

I have a linked list, and I want to sort them by names
(for example the names “Bx”, “Tx”, “Ax” would become : “Ax”, “Bx”, “Tx”)…
I need to switch the names if the one in the node’s right has a “smaller name”..

this is what I wrote:

typedef struct data
{
char *name;
}data;

typedef struct Node 
{
data NodeData;
struct Node *next;
struct Node *prev;
}Node;

void Sorting(Node *head)
{
 Node *temp = head;
 Node *temp2 = (Node*)malloc(sizeof(Node));
 while (temp != NULL)
 {
       if (1 == (strcmp(temp -> NodeData.name, temp -> next -> NodeData.name))) 
       {
              strcpy (temp2 -> NodeData.name, temp -> NodeData.name);
              strcpy (temp -> NodeData.name, temp -> next -> NodeData.name);
              strcpy (temp -> next -> NodeData.name, temp2 -> NodeData.name);
       } 

       temp = temp -> next;

 }

}

I’m getting an runtime – error on the part where I need to swarp betwen the node’s name(the strcpy lines):
An access violation (segmentation fault)…

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T04:43:19+00:00Added an answer on June 4, 2026 at 4:43 am
    if (1 == (strcmp(temp -> NodeData.name, temp -> next -> NodeData.name))) {...}
    

    When this line is executed, there is no guarantee that temp->next is not NULL.
    If it is NULL, temp->next->NodeData.Name would be rather painfull.

    Also, as has been said, testing strcmp()s result against 1 is not right. strcmp can resutning any value equal to zero, < zero or > zero.

    Also, as has been said, strcpy() is not right; the strings could have different allocated sizes, or could live in non-writable memory (string constants) . Swapping the pointers will suffice.

    UPDATE:

    void Sorting(Node *head)
    {
     Node *temp ;
    
                    /* since the compare dereferences temp->next you'll have to verify that it is not NULL */
     for (temp = head; temp && temp->next; temp = temp->next)  
     {
           if (strcmp(temp->NodeData.name, temp->next->NodeData.name) > 0 )  
           {
                    /* no need for a whole node, since you only copy a pointer */
                  char *cp;
                  cp = temp->NodeData.name;
                  temp->NodeData.name = temp->next->NodeData.name;
                  temp->next->NodeData.name = cp;
           } 
    
     }
    
    }
    

    BTW: bubble sorting a linked list is really ugly. Linked lists are easyer and more elagantly sorted by mergesort.

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