Question

I have a list ['a','b','c','d']. I need to construct a dict out of this list with all the elements of the list as keys in the dict with some default value for all the elements such as None.

How to do that? Should I need to write a function for that or is there a constructor available?

Answer 1

See dict.fromkeys().

dict.fromkeys(['a','b','c','d']) will return a dictionary with None for all of its values.

dict.fromkeys(['a','b','c','d'], foo) will return a dictionary with foo for all of its values.