Question

I have a list and an array, I wanted to find each element in the array for any range which belongs to the list.
Here is some code:

int[] number = {1, 2, 3, 5};
public List<double> m = new List<double>();
m.add(1);
m.add(1.5);
m.add(2.6);
m.add(4);
m.add(50);

For Example :
Get element in array for example 2 and i see where range (between any number in list ) answer that by list ==> 1.5 and 2.6

I want a method which will return this output :

find 1 range is {1} to {1.5} and 2 range is {1.5} to {2.6}

Answer 1

I hope I’ve got what you want.

void Main()
{
    var numbers =new [] {1, 2, 3, 5};

    //ordering to make sure that ranges is ascending order
    var orderedRanges = new []{1, 1.5, 2.6, 4, 50}.OrderBy(v => v);

    var valuesInRanges = numbers.Select(number => 
                          FormatValueInRange(
                            number,
                            orderedRanges.Last(range => range <= number ),
                            orderedRanges.First(range => range > number )));

    var result = "Find " + string.Join("and ", valuesInRanges);

    Console.WriteLine (result);
}

private string FormatValueInRange(double val, double lower, double upper)
{
    return string.Format(@"{0} is {{{1}}} to {{{2}}} ", val, lower, upper);
}

Prints:

Find 1 is {1} to {1.5} and 2 is {1.5} to {2.6} and 3 is {2.6} to {4} and 5 is {4} to {50}