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Home/ Questions/Q 8854591
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T13:55:11+00:00 2026-06-14T13:55:11+00:00

I have a list containing multiple lists as its elements eg: [[1,2,3,4],[4,5,6,7]] If I

  • 0

I have a list containing multiple lists as its elements

eg: [[1,2,3,4],[4,5,6,7]]

If I use the built in set function to remove duplicates from this list, I get the error

TypeError: unhashable type: 'list'

The code I’m using is

TopP = sorted(set(TopP),reverse=True)

Where TopP is a list just like in the e.g. Above

Is this usage of set() wrong? Is there any other way in which I can sort the above list?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T13:55:12+00:00Added an answer on June 14, 2026 at 1:55 pm

    Sets require their items to be hashable. Out of types predefined by Python only the immutable ones, such as strings, numbers, and tuples, are hashable. Mutable types, such as lists and dicts, are not hashable because a change of their contents would change the hash and break the lookup code.

    Since you’re sorting the list anyway, just place the duplicate removal after the list is already sorted. This is easy to implement, doesn’t increase algorithmic complexity of the operation, and doesn’t require changing sublists to tuples:

    def uniq(lst):
        last = object()
        for item in lst:
            if item == last:
                continue
            yield item
            last = item
    
    def sort_and_deduplicate(l):
        return list(uniq(sorted(l, reverse=True)))
    
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