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Editorial Team
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Asked: 2026-06-14T14:08:45+00:00

I have a list: /device1/element1/CmdDiscovery /device1/element1/CmdReaction /device1/element1/Direction /device1/element1/MS-E2E003-COM14/Field2 /device1/element1/MS-E2E003-COM14/Field3 /device1/element1/MS-E2E003-COM14/NRepeatLeft How can I grep

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I have a list: 

/device1/element1/CmdDiscovery
/device1/element1/CmdReaction
/device1/element1/Direction
/device1/element1/MS-E2E003-COM14/Field2
/device1/element1/MS-E2E003-COM14/Field3
/device1/element1/MS-E2E003-COM14/NRepeatLeft

How can I grep so that the returned strings containing only "Field" followed by digits or simply NRepeatLeft at the end of string (in my example it will be the last three strings)?

Expected output:

/device1/element1/MS-E2E003-COM14/Field2
/device1/element1/MS-E2E003-COM14/Field3
/device1/element1/MS-E2E003-COM14/NRepeatLeft
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1 Answer

  1. Editorial Team

    Try doing this :

    grep -E "(Field[0-9]*|NRepeatLeft$)" file.txt
      |  |           |           ||
      |  |          OR   end_line |
      | opening_choice   closing_choice
 extented_grep

    if you don’t have -E switch (stands for ERE : Extented Regex Expression):

    grep "\(Field[0-9]*\|NRepeatLeft$\)" file.txt

    OUTPUT

    /device1/element1/MS-E2E003-COM14/Field2
/device1/element1/MS-E2E003-COM14/Field3
/device1/element1/MS-E2E003-COM14/NRepeatLeft

    That will grep for lines matching Field[0-9] or lines matching RepeatLeft at the end. Is it what you expect ?

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