Question

I have a list:

list = [ '1', '1,'1', '-1','1','-1' ]

and need to convert it to a dictionary of dictionaries. The first three values in are x y z and the second set three values are x y z. The result should be:

d = { 0:{x:1,y:1,z:1}, 1:{x:-1,y:1,z:-1}}

My attempt:

mylist=[1,1,1,-1,1,-1]
count = 1
keycount = 0
l = {'x':' ','y':' ', 'z':' '}
t = {}
for one in mylist:
        if count == 1:
                l['x'] = one
                print l
        if count == 2:
                l['y'] = one
                print l
        if count == 3:
                l['z'] = one
                print l
                count = 0
                t[keycount] = l
                l = {}
                keycount += 1
        count = count + 1
print t

But in the result it switches some of the keys of the dictionary? Does anyone have a better solution?

Answer 1

A bit complicated one:

l = [ '1', '1', '1', '-1', '1', '-1' ]

dicts = [dict(zip(['x', 'y', 'z'], l[i:i+3])) for i in range(0, len(l), 3)]
result = dict(enumerate(dicts))

print result #prints {0: {'y': '1', 'x': '1', 'z': '1'}, 1: {'y': '1', 'x': '-1', 'z': '-1'}}