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Home/ Questions/Q 9189953
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T20:21:04+00:00 2026-06-17T20:21:04+00:00

I have a list of dozens DIVs like <div data-sort=7.5></div> <div data-sort=3.2></div> <div data-sort=2.15></div>

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I have a list of dozens DIVs like

<div data-sort="7.5"></div>
<div data-sort="3.2"></div>
<div data-sort="2.15"></div>
<div data-sort="-1.78"></div>
<div data-sort="-2.39"></div>

and so on and I get new DIVs with an ajax request. I need to insert the new DIV so the order with “data-sort” remains intact in descending order.

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  1. Editorial Team
    Editorial Team
    2026-06-17T20:21:06+00:00Added an answer on June 17, 2026 at 8:21 pm

    It’s not as optimal as can be, but I would just sort the divs each time the ajax request completes:

    $("div").sort(function (prev, next) {
        return parseInt(next.dataset.sort) - parseInt(prev.dataset.sort);
    }).appendTo("body");
    

    If that takes too long, you’ll just have to cycle through the divs (via .each?) and find the first one whose data-sort is smaller.

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