Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 520105
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T08:06:37+00:00 2026-05-13T08:06:37+00:00

I have a List of Foo Objects. If a name appears multiple times, I

  • 0

I have a List of Foo Objects. If a name appears multiple times, I want to do something to the first Item with that name.

HashMap<String, Foo> map = new HashMap<String, Foo>();
for (Foo bar: this.FooList)
{
    if (!map.containsKey(bar.getName()))
    {
        map.put(bar.getName(), bar);
    }
    else
    {
        map.get(bar.getName()).doSomeThing();
    }
}

But this is not working, because every name (unique or not) gets thrown in that map. Does the HashMap check only for reference equality and not equality on key objects?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T08:06:37+00:00Added an answer on May 13, 2026 at 8:06 am

    This is the code you need:

        HashMap<String, Foo> map = new HashMap<String, Foo>();
        for (Foo bar: this.FooList)
        {
            if (!map.containsKey(bar.getName()))
            {
                map.put(bar.getName(), bar);
            }
            else
            {
                Foo foo = map.get(bar.getName());
                if (foo != null)
                    foo.doSomeThing();
                map.put(bar.getName(), null);
            }
        }
    

    Here’s a testbed for it:

    import java.util.HashMap;
    import java.util.ArrayList;
    
    public class Example
    {
        public static void main(String[] args)
        {
            new Example().run();
        }
    
        private ArrayList<Foo> FooList = new ArrayList<Foo>();
    
        public void run()
        {
            FooList.add(new Foo("abc", 1));
            FooList.add(new Foo("abc", 2));
            FooList.add(new Foo("def", 3));
            FooList.add(new Foo("abc", 4));
            FooList.add(new Foo("abc", 5));
            FooList.add(new Foo("ghi", 6));
            FooList.add(new Foo("def", 7));
    
            HashMap<String, Foo> map = new HashMap<String, Foo>();
            for (Foo bar: this.FooList)
            {
                if (!map.containsKey(bar.getName()))
                {
                    map.put(bar.getName(), bar);
                }
                else
                {
                    Foo foo = map.get(bar.getName());
                    if (foo != null)
                        foo.doSomeThing();
                    map.put(bar.getName(), null);
                }
            }
        }
    
        class Foo
        {
            public Foo(String name, int i)
            {
                this.name = name;
                this.i = i;
            }
    
            public String getName()
            {
                return name;
            }
    
            public void doSomeThing()
            {
                System.out.println(getName() + " " + i);
            }
    
            private String name;
            private int i;
        }
    }
    

    Output is:

    abc 1
    def 3
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 285k
  • Answers 285k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer In Vista streaming such as video and audio get a… May 13, 2026 at 4:43 pm
  • Editorial Team
    Editorial Team added an answer With the risk of oversimplifying things: why not make the… May 13, 2026 at 4:43 pm
  • Editorial Team
    Editorial Team added an answer You could, as suggested, use an UpdatePanel. As long as… May 13, 2026 at 4:43 pm

Related Questions

Scheme uses a single namespace for all variables, regardless of whether they are bound
I have a View class (OrderView.aspx) which shows the details of an order (Account
I have a class that is maps to a field in a database. The
If I have an example function ... function foo() { # get a list
I have ObservableCollection<Foo> that is bound to an ItemsControl (basically displaying a list). Foo

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.