Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 921205
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T18:50:10+00:00 2026-05-15T18:50:10+00:00

I have a list of objects. The objects are given an ID and stored

  • 0

I have a list of objects. The objects are given an ID and stored in a Hashtable. If I need an object with particular ID, I simply say:

ht.get(ID);

However, sometimes I need to get the ID for a given object:

ht.get(Object);

My first idea is to use two different HashTables; one for ID -> Object mapping and the other for Object -> ID mapping.

Does this sound like a good enough solution?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T18:50:10+00:00Added an answer on May 15, 2026 at 6:50 pm

    If you cannot use external collections (as you seem to not want to use given one of your comments) you could write a simple class to do what you want (which, yes, is essentially your first thought), along the lines of (I didn’t compile this, and it is just a first thought so could be a bad idea, etc …):

    EDIT: now there are two versions, one that allows for duplicate values and one that does not. The ones that does not will remove the key if the value is overwritten.

    This version does not allow duplicate values:

    class Foo<K, V>
    {
        private final Map<K, V> keyValue;
        private final Map<V, K> valueKey;
    
        {
            keyValue = new HashMap<K, V>();
            valueKey = new HashMap<V, K>();
        }
    
        // this makes sure that if you do not have duplicate values.
        public void put(final K key, final V value)
        {
            if(keyValue.containsValue(value))
            {
                keyValue.remove(valueKey.get(value));
            }
    
            keyValue.put(key, value);
            valueKey.put(value, key);
        }
    
        public V getValueForKey(final K key)
        {
            return (keyValue.get(key));
        }
    
        public K getKeyForValue(final V value)
        {
            return (valueKey.get(value));
        }
    
        public static void main(final String[] argv)
        {
            Foo<String, String> foo;
    
            foo = new Foo<String, String>();
            foo.put("a", "Hello");
            foo.put("b", "World");
            foo.put("c", "Hello");
    
            System.out.println(foo.getValueForKey("a"));
            System.out.println(foo.getValueForKey("b"));
            System.out.println(foo.getValueForKey("c"));
    
            System.out.println(foo.getKeyForValue("Hello"));
            System.out.println(foo.getKeyForValue("World"));
        }
    }
    

    This version allows duplicated values and gives you back a list of all of the keys that have a given value:

    class Foo<K, V>
    {
        private final Map<K, V> keyValue;
        private final Map<V, List<K>> valueKeys;
    
        {
            keyValue = new HashMap<K, V>();
            valueKeys = new HashMap<V, List<K>>();
        }
    
        public void put(final K key, final V value)
        {
            List<K> values;
    
            keyValue.put(key, value);
    
            values = valueKeys.get(value);
    
            if(values == null)
            {
                values = new ArrayList<K>();
                valueKeys.put(value, values);
            }
    
            values.add(key);
        }
    
        public V getValueForKey(final K key)
        {
            return (keyValue.get(key));
        }
    
        public List<K> getKeyForValue(final V value)
        {
            return (valueKeys.get(value));
        }
    
        public static void main(final String[] argv)
        {
            Foo<String, String> foo;
    
            foo = new Foo<String, String>();
            foo.put("a", "Hello");
            foo.put("b", "World");
            foo.put("c", "Hello");
    
            System.out.println(foo.getValueForKey("a"));
            System.out.println(foo.getValueForKey("b"));
            System.out.println(foo.getValueForKey("c"));
    
            System.out.println(foo.getKeyForValue("Hello"));
            System.out.println(foo.getKeyForValue("World"));
        }
    }
    

    Hiding the two maps in a class is a good idea, because of you find a better way later all you need to do is replace the innards of the class and the rest of your code is left untouched.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a list of objects: [Object_1, Object_2, Object_3] Each object has an attribute:
I have List objects which are shown like this: www.mysite.com/lists/123 Where 123 is the
I have 2 List objects: List<int> lst1 = new List<int>(); List<int> lst2 = new
I have List where myObj has it own list of objects called example mySubObj.
I have a list of objects and I want to remove all the ones
I have a list of objects (mainly int, string, double) And I would like
I have a list of objects which uses paging in my home > index.cshtml.
I have a list of custom objects List and I would like to update
I have a list of objects that have two int properties. The list is
I have a list of objects called Activity: class Activity { public Date activityDate;

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.