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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T11:28:59+00:00 2026-06-04T11:28:59+00:00

I have a list of Objects which are not comparable. I however would still

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I have a list of Objects which are not comparable. I however would still like to sort this list of Objects based on a provided array of index positions. What is the fastest and most efficient way to sort this list? Here is an example:

List<Colour> list = new ArrayList<Colour>();
list.add(Colour.BLUE);
list.add(Colour.GREEN);
list.add(Colour.RED);
list.add(Colour.YELLOW);
list.add(Colour.GREEN);

int[] order = new int[] {3, 1, 2, 0, 4};

The final list should look like:

[YELLOW, GREEN, RED, BLUE, GREEN]

My specific requirement is for a solution in Java but I would be interested to know the solution in other languages as well.

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  1. Editorial Team
    Editorial Team
    2026-06-04T11:29:00+00:00Added an answer on June 4, 2026 at 11:29 am

    Why don’t you just create the list from the indexes directly? No “sorting” is required.

    List<Colour> sortedList = new ArrayList<Colour>();
    for (int index : order) {
        sortedList.add(list.get(index));
    }
    

    Or C#:

    var sorted = order.Select(index => list[index]).ToList();
    
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