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Home/ Questions/Q 7717261
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T02:50:35+00:00 2026-06-01T02:50:35+00:00

I have a List of objects which are ordered. I would like to remove

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I have a List of objects which are ordered. I would like to remove redundant objects where redundant does not necessarily mean duplicate. Here is an example:

List<Point> points = new List<Point>
{
   new Point(0, 10),
   new Point(1, 12),
   new Point(2, 16),
   new Point(3, 16),
   new Point(4, 16),
   new Point(5, 13),
   new Point(6, 16),
};

I am interested in removing the new Point(3, 16) entry because it doesn’t provide useful information; I already know that the element at 2=16 and the element at 4=16. The information that 3=16 doesn’t do me any good in my application (because I already have the bounds {2,4}=16), so I would like to remove that entry. I’d also like to not that I want to keep the 5th and 6th entry because there are not consecutive entries where Y=16.

Is there a slick way to do this with linq?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T02:50:37+00:00Added an answer on June 1, 2026 at 2:50 am

    What about this?

    public void Test()
    {
     List<Point> points = new List<Point>
     {
      new Point(0, 10),
      new Point(1, 12),
      new Point(2, 16),
      new Point(3, 16),
      new Point(4, 16),
      new Point(5, 13),
      new Point(6, 16),
     };
     var subSetOfPoints = points.Where(p=> !IsInTheMiddleX(p, points));
    }
    
    private bool IsInTheMiddleX(Point point, IEnumerable<Point> points)
    {
     return points.Any(p => p.X < point.X && p.Y == point.Y) && 
            points.Any(p => p.X > point.X && p.Y == point.Y);                        
    }
    
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