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Home/ Questions/Q 8705469
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T03:21:57+00:00 2026-06-13T03:21:57+00:00

I have a list of outerItems. Inside each outerItem, I have a list of

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I have a list of outerItems. Inside each outerItem, I have a list of innerItems. They are dynamically sorted.

When mouse cursor points at one of innerItems, I have to show the popup window right above that innerItem element.

Popup div is body’s child, because I do not want to have a separate popup for each of innerItems.

The way as I see it — on ng-mouseover I call the function that sets left/top properties to my absolutely positioned popup. So for each of innerItems I’d like to call jQuery .offset() method that gives me left/top values from the top-left corner of page.

So how can I get jQuery object of current scope element? Or, if I’ve chosen the wrong way

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  1. Editorial Team
    Editorial Team
    2026-06-13T03:21:58+00:00Added an answer on June 13, 2026 at 3:21 am

    In controller:

    function innerItem($scope, $element){
        var jQueryInnerItem = $($element); 
    }
    
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