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Home/ Questions/Q 449081
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T21:44:02+00:00 2026-05-12T21:44:02+00:00

I have a list of random integers. I’m wondering which algorithm is used by

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I have a list of random integers. I’m wondering which algorithm is used by the list::sort() method. E.g. in the following code:

list<int> mylist;

// ..insert a million values

mylist.sort();

EDIT: See also this more specific question.

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  1. Editorial Team
    Editorial Team
    2026-05-12T21:44:02+00:00Added an answer on May 12, 2026 at 9:44 pm

    The standard doesn’t require a particular algorithm, only that it must be stable, and that it complete the sort using approximately N lg N comparisons. That allows, for example, a merge-sort or a linked-list version of a quick sort (contrary to popular belief, quick sort isn’t necessarily unstable, even though the most common implementation for arrays is).

    With that proviso, the short answer is that in most current standard libraries, std::sort is implemented as a intro-sort (introspective sort), which is basically a Quicksort that keeps track of its recursion depth, and will switch to a Heapsort (usually slower but guaranteed O(n log n) complexity) if the Quicksort is using too deep of recursion. Introsort was invented relatively recently though (late 1990’s). Older standard libraries typically used a Quicksort instead.

    stable_sort exists because for sorting array-like containers, most of the fastest sorting algorithms are unstable, so the standard includes both std::sort (fast but not necessarily stable) and std::stable_sort (stable but often somewhat slower).

    Both of those, however, normally expect random-access iterators, and will work poorly (if at all) with something like a linked list. To get decent performance for linked lists, the standard includes list::sort. For a linked list, however, there’s not really any such trade-off — it’s pretty easy to implement a merge-sort that’s both stable and (about) as fast as anything else. As such, they just required one sort member function that’s required to be stable.

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