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Home/ Questions/Q 6662419
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T02:23:15+00:00 2026-05-26T02:23:15+00:00

I have a list of table elements under element named Query that may duplicate,

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I have a list of table elements under element named Query that may duplicate, I need to fetch distinct table elements (not its value but the tag/element name itself.

/ShopArea/Connection/Query/* lists the table names including duplicates.

Below is the XML

<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="ShopArea.xslt"?>
<ShopArea>
<Connection name="Connection1">
    <Report date="25-09-2011">

        <Query id="1">
            <TABLE1>1.1</TABLE1>
            <TABLE2>1.2</TABLE2>
            <TABLE3>1.3</TABLE3>
        </Query>
        <Query id="2">
            <TABLE21>2.1</TABLE21>
            <TABLE22>2.2</TABLE22>
            <TABLE23>2.3</TABLE23>
        </Query>
    </Report>

    <Report date="26-09-2011">
        <Query id="1">
            <TABLE1>26 1.1</TABLE1>
            <TABLE2>26 1.2</TABLE2>
            <TABLE3>26 1.3</TABLE3>
        </Query>
        <Query id="2">
            <TABLE21>26 2.1</TABLE21>
            <TABLE22>26 2.2</TABLE22>
            <TABLE23>26 2.3</TABLE23>
        </Query>
    </Report>
</Connection>
</ShopArea>

List of elements including duplicates

I refered How to select unique nodes in XSLT but I’m not able to get it right.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T02:23:15+00:00Added an answer on May 26, 2026 at 2:23 am

    I. XSLT 1.0. This transformation uses simple Muenchian grouping:

    <xsl:stylesheet version="1.0"
     xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
     <xsl:output omit-xml-declaration="yes" indent="yes"/>
    
     <xsl:key name="kChildByName" match="Query/*"
      use="name()"/>
    
     <xsl:template match=
      "Query/*
           [generate-id()
           =
            generate-id(key('kChildByName', name())[1])
           ]">
         <xsl:value-of select="name()"/>
         <xsl:text>&#xA;</xsl:text>
     </xsl:template>
    
     <xsl:template match="text()"/>
    </xsl:stylesheet>
    

    When applied on the provided XML document:

    <ShopArea>
        <Connection name="Connection1">
            <Report date="25-09-2011">
                <Query id="1">
                    <TABLE1>1.1</TABLE1>
                    <TABLE2>1.2</TABLE2>
                    <TABLE3>1.3</TABLE3>
                </Query>
                <Query id="2">
                    <TABLE21>2.1</TABLE21>
                    <TABLE22>2.2</TABLE22>
                    <TABLE23>2.3</TABLE23>
                </Query>
            </Report>
            <Report date="26-09-2011">
                <Query id="1">
                    <TABLE1>26 1.1</TABLE1>
                    <TABLE2>26 1.2</TABLE2>
                    <TABLE3>26 1.3</TABLE3>
                </Query>
                <Query id="2">
                    <TABLE21>26 2.1</TABLE21>
                    <TABLE22>26 2.2</TABLE22>
                    <TABLE23>26 2.3</TABLE23>
                </Query>
            </Report>
        </Connection>
    </ShopArea>
    

    the wanted, correct result (all different names of elements that are children of a Query) is produced:

    TABLE1
    TABLE2
    TABLE3
    TABLE21
    TABLE22
    TABLE23
    

    II. XSLT 2.0: This transformation uses <xsl:for-each-group>:

    <xsl:stylesheet version="2.0"
        xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
        xmlns:xs="http://www.w3.org/2001/XMLSchema">
        <xsl:output omit-xml-declaration="yes" indent="yes"/>
    
     <xsl:template match="/*/*">
         <xsl:for-each-group select="Report/Query/*"
                             group-by="name()">
          <xsl:sequence select="current-grouping-key(), '&#xA;'"/>
         </xsl:for-each-group>
     </xsl:template>
    
     <xsl:template match="text()"/>
    </xsl:stylesheet>
    
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