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Home/ Questions/Q 287909
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T05:46:06+00:00 2026-05-12T05:46:06+00:00

I have a list of tuples, each containing a find/replace value that I would

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I have a list of tuples, each containing a find/replace value that I would like to apply to a string. What would be the most efficient way to do so? I will be applying this iteratively, so performance is my biggest concern.

More concretely, what would the innards of processThis() look like?

x = 'find1, find2, find3'
y = [('find1', 'replace1'), ('find2', 'replace2'), ('find3', 'replace3')]

def processThis(str,lst):
     # Do something here
     return something

>>> processThis(x,y)
'replace1, replace2, replace3'

Thanks, all!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T05:46:06+00:00Added an answer on May 12, 2026 at 5:46 am

    You could consider using re.sub:

    import re
    REPLACEMENTS = dict([('find1', 'replace1'),
                         ('find2', 'replace2'),
                         ('find3', 'replace3')])
    
    def replacer(m):
        return REPLACEMENTS[m.group(0)]
    
    x = 'find1, find2, find3'
    r = re.compile('|'.join(REPLACEMENTS.keys()))
    print r.sub(replacer, x)
    
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