Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7943253
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 4, 20262026-06-04T00:13:01+00:00 2026-06-04T00:13:01+00:00

I have a list of xts objects. I’d like to get a data.frame with

  • 0

I have a list of xts objects. I’d like to get a data.frame with the last lines of each levels of the list.

My list looks like:

a <- xts(matrix(1:4,2),as.Date("2012-01-01")+0:1)
b <-list(a,a*5)
> b
[[1]]
           [,1] [,2]
2012-01-01    1    3
2012-01-02    2    4

[[2]]
           [,1] [,2]
2012-01-01    5   15
2012-01-02   10   20

I would like to get:

[,1] [,2]
2    4
10   20

The column names are the same in each levels of the list.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-04T00:13:04+00:00Added an answer on June 4, 2026 at 12:13 am

    In addition to @Henrik’s answer, you could also use a combination of lapply, do.call, and last:

    do.call(rbind,lapply(b,last))
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have list List<Employee> it contains data like Name Year Salary John 2001 10000
I have List objects which are shown like this: www.mysite.com/lists/123 Where 123 is the
I have list of some data items. Each has a method GetStyle which returns
I have list like this. <li data-pet=cat></li> <li data-pet=cat></li> <li data-pet=cat></li> <li data-pet=dog></li> Using
I have List collection with around 35,000 strings Typical string looks like this: <i>füüs</i>ampri
I have List of User object, I just want to get User objects from
I am having trouble working with a list of xts objects. I get different
Assume: list of n xts objects in .GlobalEnv with the suffix .raw (e.g: ABC.raw
I have generalized the existing Data.List.partition implementation partition :: (a -> Bool) -> [a]
I have a df/zoo/xts/whatever that is split by day of week. I'd like to

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.