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Home/ Questions/Q 6116015
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T15:09:28+00:00 2026-05-23T15:09:28+00:00

I have a list structure like this: <ul id=part> <?php $i=0; foreach ($q as

  • 0

I have a list structure like this:

  <ul id="part">   
    <?php 
      $i=0; 
      foreach ($q as  &$value):
        $i++;
        $quid = $value->q_id;
        $ans= $this->mem->get_ans($quid);
        echo '<li id="div'.$i.'" class="ques" style="display: none;">';
        echo '  <h2>'.$i.' . '.$value->question.'</h2>';              
                foreach($ans as $answer):
                  echo '<label>';
                  echo '<input type="checkbox" value="'.$answer->ans_id.'" />';
                  echo $answer->ans_name;
                  echo '</label>';
                endforeach;
        echo '</li>';
      endforeach; ?>
      <button id="next">Next</button>
    </ul>

I want the following: When someone clicks the button #next, then it will show the next list item and further on. How can I achieve this with jQuery?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T15:09:29+00:00Added an answer on May 23, 2026 at 3:09 pm

    Move your <button> tag outside of <ul> only <li> (list items) are valid inside an unordered list.

    The JavaScript (using jQuery) needed to do what you are asking is below:

    $(function() {
    
        //cache the items for quicker access       
        var items = $('ul#part li');
    
        //bind your event to #next
        $('#next').click(function() {
    
           //Check if no elements are visible yet.
           if(items.filter(':visible').length == 0) {
             items.first().show();
           }
           else {
             //Otherwise, select the last visible one, 
             //then transverse to the next one and show it
             items.filter(':visible:last').next().show();
           }
    
        });
    
    });
    
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