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Home/ Questions/Q 8044197
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T05:09:04+00:00 2026-06-05T05:09:04+00:00

I have a list that that looks like this: (‘string ‘, ‘time’, ‘SPY’, 0,

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I have a list that that looks like this:

('string ', 'time', 'SPY', 0, 0, 131.63, 100),
('sting ', 'time', 'SPY', 0, 0, 131.63, 700)

what I want to do is add the last column of data

What I though to do is unzip the list and then sum the absolute value of the date in the last column but I cant get it to work correctly

what I have been trying is this:

testsum = sum(abs(zip(*list[:-1]))

thanks

EDIT:
Ok so thanks for the response

sum(l[-1]) for l in list

worked well but I forgot to mention that I have it running in a for loop and what I really want to do is add all the sums that are outputted I’m really confused and am unsure how to do that I though I could do the same thing again but it didnt work

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  1. Editorial Team
    Editorial Team
    2026-06-05T05:09:07+00:00Added an answer on June 5, 2026 at 5:09 am

    Generator expressions are your friend:

    sum(l[-1] for l in list)
    

    (although I do hope your list isn’t literally called ‘list’, since that would shadow the builtin).

    For the followup, it does depend on exactly what you mean by ‘add all the sums that are outputted’. This could mean have some number of lists like the one you posted that you’re iterating over, and you want to add all the sums together once. This would be:

    sum(sum(l[-1] for l in list) for list in lists)
    

    Or even just

    sum(l[-1] for l in list for list in lists)
    

    If you mean you want a cumulative sum – so, you want the running total at each stage as another inner sum is added to it – take a look at this previous question about cumulative sums, or just write out the loop:

    cumsum = 0
    for list in lists:
       cumsum += sum(l[1] for l in list)
       print(cumsum)
    
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