Question

I have a list which is shown below.

plist = [('s', [0.0, 0.1, 0.0, 0.4, 0.0]),
         ('aa', [0.0, 0.1, 0.0, 0.5, 0.0]),
         ('m', [0.0, 0.0, 0.1, 0.3, 0.0]),
         ('ih', [0.0, 0.1, 0.1, 0.2, 0.0]),
         ('k', [0.0, 0.1, 0.0, 0.1, 0.0]),
         ('l', [0.0, 0.1, 0.0, 0.6, 0.0]),
         ('eh', [0.0, 0.1, 0.0, 0.0, 0.0]),
         ('k', [0.0, 0.1, 0.0, 0.0, 0.0]),
         ('t', [0.0, 0.1, 0.0, 0.1, 0.0]),
         ('aa', [0.0, 0.1, 0.0, 0.0, 0.0]),
         ('n', [0.0, 0.1, 0.1, 0.2, 0.0]),
         ('ih', [0.0, 0.1, 0.1, 0.0, 0.0]),
         ('t', [0.0, 0.1, 0.0, 0.0, 0.0]),
         ('g', [0.0, 0.1, 0.0, 0.4, 0.0]),
         ('eh', [0.0, 0.1, 0.0, 0.0, 0.0]),
         ('l', [0.0, 0.1, 0.0, 0.5, 0.0]),
         ('v', [0.3, 0.0, 0.1, 0.1, 0.0]),
         ('ae', [0.0, 0.1, 0.1, 0.0, 0.0]),
         ('n', [0.0, 0.1, 0.1, 0.2, 0.0]),
         ('ih', [0.0, 0.1, 0.1, 0.0, 0.0]),
         ('k', [0.0, 0.1, 0.0, 0.0, 0.0]),
         ('aa', [0.0, 0.1, 0.0, 0.0, 0.0]),
         ('p', [0.0, 0.0, 0.3, 0.0, 0.0]),
         ('l', [0.0, 0.1, 0.2, 0.0, 0.0]),
         ('k', [0.0, 0.1, 0.1, 0.0, 0.0])]

I want to create five different lists by taking out the values from this list. The first list will have the first values of all the keys, the second will have the second values of the keys and so on. I also don’t need the keys in these new lists and only the values.Thank you.

Answer 1

You can separate out all of the data with:

v = [[row[1][i] for row in plist] for i in range(len(plist[0][1]))]

Now you have one list where v[0] is the first set of values, v[1] is the second set, and so on. If you still want five separate lists, you can now do:

v0 = v[0]
v1 = v[1]
.
.
.