Home/ Questions/Q 9158499
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-06-17T13:15:39+00:00

I have a ListView with a custom adapter. In every row there is an

  • 0

I have a ListView with a custom adapter. In every row there is an ImageView that is visible only under certain constraints. The problem is that if the first row has this ImageView visible, so it is for the last row as well and viceversa.

Here is the getView() code of my adapter.

public View getView(int position, View view, ViewGroup parent) {
    if (view == null) {
        LayoutInflater inflater = (LayoutInflater) mContext
                .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        view = inflater.inflate(R.layout.row_idea, null);
    }

    Idea idea = mIdeas.get(position);

    if (idea != null) {
        ImageView imgAlarm = (ImageView) view
                .findViewById(R.id.imgAlarm_rowIdea);
        if (idea.getTimeReminder() != null)
            imgAlarm.setVisibility(ImageView.VISIBLE);

        TextView lblTitle = (TextView) view
                .findViewById(R.id.lblTitle_rowIdea);
        lblTitle.setText(idea.getTitle());

        TextView lblDescription = (TextView) view
                .findViewById(R.id.lblDescription_rowIdea);
        lblDescription.setText(idea.getDescription());
    }
    return view;
}

mIdeas is an ArrayList with all the data to display in the ListView.
imgAlarm is the ImageView that I told above.

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    Change

    if (idea.getTimeReminder() != null)
            imgAlarm.setVisibility(ImageView.VISIBLE);

    to

    if (idea.getTimeReminder() != null)
            imgAlarm.setVisibility(ImageView.VISIBLE);
else
            imgAlarm.setVisibility(ImageView.GONE);

    What’s happening here is that the adapter is “recycling” the views. So in the case you’re seeing in your tests, the last view and the first view are actually the same instance.

    • 0