Question

I have a “little” problem because I don’t know whats the best way to handle ajax jquery database request?

So far I’ve done it this way:
For ever (single) database request I created a new .php file like:

newbill.php
newcosumer.php
listallbills.php
updatecostumer.php

..and so on and pull the data via:

$.ajax({
 type: "POST",
    url: "ajax/newbill.php",
    data: "..."
    success: function(msg){    
    ...
    }
 }); 

..what I don’t like is all the .php files for only ONE! database request!?
There must be a better way to handle this??

Answer 1

I would do it in this way.

Create a php file for each entity (Ex : consumerajax.php , billajax.php,etc…) then have seperate functions for each of your database queries.When calling from the javascript pass a querystring variable to determine which function to be executed in the ajax server page

Ex : In consumerajax.php

 <?php

    $mode= $_GET["mode"] ;
    if($mode=="getconsumerdet")
    {
       $consumerId=$_GET["cid"];
       GetConsumerDetails($consumerId)
    }
    else if($mode=="updateconsumer")
    {
      $consumerId=$_GET["cid"];
      $name=$_GET["name"];
      UpdateConsumerInfo($consumerId, $name)
    }

    function GetConsumerDetails($consumerId)
    {
       // execute query the table here and return the result from here
      echo"Have the data and return"
    } 
    function UpdateConsumerInfo($consumerId,$name)
    {
      //execute query to update
     echo "updated";
    }

?>

and from your scrip call like

  $.ajax({ type: "POST", url: "ajax/consumerajax.php?mode=getconsumerdet&cid=34", data: "..." success: function(msg){   });

or

  $.ajax({ type: "POST", url: "ajax/consumerajax.php?mode=updateconsumer&cid=34&name=shyju", data: "..." success: function(msg){   });