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Home/ Questions/Q 1022677
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T11:30:06+00:00 2026-05-16T11:30:06+00:00

I have a little problem when i try to clone an element with jquery

  • 0

I have a little problem when i try to clone an element with jquery basically I Have this, i want to clone the div called clone and put in other div in some where else.

<li class="jqModal"  >
    <div class="clone">
    <div class="image">
            <img src="<?php echo $products[$j]['thumb']; ?>"
                 title="<?php echo $products[$j]['name']; ?>" alt="<?php echo $products[$j]['name']; ?>" />
    </div>
    <h2><a href=""><?php echo $products[$j]['name']; ?></a></h2>
    <strong class="price"><?php echo $products[$j]['price']; ?></strong>
    <a href="<?php echo $products[$j]['href']; ?>">More details</a>
    </div>


</li>`

I use this in my document ready

$(document).ready(function () {
   $(".product-list li").hover(
      function () {
         //replace image and id
         $var = $(this).clone(false).find("#clone").
         $('#div-to-replace').replaceWith($var);
      }
   );
});

But its not working any advice, thank you in advance. 🙂

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  1. Editorial Team
    Editorial Team
    2026-05-16T11:30:06+00:00Added an answer on May 16, 2026 at 11:30 am

    Try this:

    $(".product-list li").hover(
        function () {
            //replace image and id
            $var = $('.clone', this).clone();
            $('#div-to-replace').replaceWith($var);
        }
    );
    

    Changes to your code:

    1. You want to clone the element with the class “clone”, not the id: #clone -> .clone
    2. If you clone first and then find the element, then you’re cloning too much, so I changed the selector for cloning
    3. At the end of this line there’s a dot where should be a semicolon.​
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