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Home/ Questions/Q 8958259
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T15:10:16+00:00 2026-06-15T15:10:16+00:00

i have a little problem with my javascript code, i build a function that

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i have a little problem with my javascript code,
i build a function that add filed by a qty that the user choose,
here is the function

$(document).ready(function() {
  $('.qty').change(function(){
     for (var i=0;i<$('.qty').val();i++){
       $('.append').append('<select name="data[]"><option value="one">1</option></select>');
     }
  });
});

AND the html code is:

<select name="qty" class="qty">
            <option value="1">1</option>
            <option value="2">2</option>
            <option value="3">3</option>
            <option value="4">4</option>
            <option value="5">5</option>
</select>
<div class="append">

</div>

when i pick a value in the qty, lets say 3, it open me up 3 select fields, but when i change the selection to 2, it adds me 2, so i have 5 select fileds, how do i reset? if i pick 1 it will open me 1 and if i change it to 2 it will change and open me 2 not 3 like it is now.

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  1. Editorial Team
    Editorial Team
    2026-06-15T15:10:17+00:00Added an answer on June 15, 2026 at 3:10 pm

    Try:

    $(document).ready(function() {
      $('.qty').change(function(){
        var html=''
         for (var i=0;i< parseInt($('.qty').val());i++){
           html += '<select name="data[]"><option value="one">1</option></select>';
         }
         $('.append').html(html);
      });
    });
    
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