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Home/ Questions/Q 8583215
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T21:28:51+00:00 2026-06-11T21:28:51+00:00

I have a local storage as follows Key0 is key and its value is

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I have a local storage as follows

Key0 is key and its value is {“fav1,fav2,fav3,fav4,fav5”}

If i use localstorage.removeitem(‘key0’), whole value is completely removed

How do i specifically remove fav1 or fav2 or such using removeitem function or is there any simple way to remove a specific part of local storage

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  1. Editorial Team
    Editorial Team
    2026-06-11T21:28:52+00:00Added an answer on June 11, 2026 at 9:28 pm

    There is no simple way of doing this since the value you store under a specific key is just a string. So, if you store "fav1,fav2,fav3,fav4,fav5" under the key key0, then this value is just a string like any other (e.g. foobar). If you want to change that string which is stored in localStorage, you have to 1) read it from localStorage, 2) change it manually, and then 3) store it back into localStorage under the same key.

    The way this is usually done is by using JSON serialization and deserialization:

    key = "key0";
    value = JSON.stringify(["fav1", "fav2", "fav3", "fav4", "fav5"]);
    // value is now the JSON string representing the array
    localStorage.setItem(key, value);
    
    newValue = JSON.parse(localstorage.getItem(key))
    // newValue is now an array with the values fav1, fav2, ... so we can manipulate it and store it back
    newValue.pop();
    newValue = JSON.stringify(newValue);
    localStorage.setItem(key, newValue);
    
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