Question

I have a log file containing such output:

  [mvn] Running com.mypackage.MyTest
   ...
  [mvn] Tests run: 12, Failures: 0, Errors: 0, Skipped: 0, Time elapsed: 104.648 sec
  [mvn] Running com.mypackage.MyNotExecutedTest
   ...
  [mvn] Tests run: 0, Failures: 0, Errors: 0, Skipped: 0, Time elapsed: 0.525 sec
  [mvn] Running com.mypackage.AnotherNotExecutedTest
   ...
  [mvn] Tests run: 0, Failures: 0, Errors: 0, Skipped: 0, Time elapsed: 0.569 sec
  [mvn] Running com.mypackage.FailedTest
   ...
  [mvn] Tests run: 5, Failures: 2, Errors: 0, Skipped: 0, Time elapsed: 22.357 sec
   ...

whereas there can be any arbitrary number of lines where “…” is (e.g. stack trace, some debug output). What I want to achieve is a list of tests which hasn’t been executed:

  com.mypackage.MyNotExecutedTest
  com.mypackage.AnotherNotExecutedTest

So my approach was to grep for pattern “Tests run: 0, Failures: 0, Errors: 0, Skipped: 0, Time elapsed” but then I would somehow need a smart way to find out what Test belongs the grep pattern.
Any good/elegant solutions here? Thanks!

Answer 1

Write an awk script which stores the latest Running line, then prints the stored line if it sees Tests run: 0.

awk '/\[mvn\] Running /{ t=$3 }
  /\[mvn\] Tests run: 0/ { print t }'  logfile

Edit: I took out the line beginning anchors, in order to correctly cope with indented input.