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Asked: 2026-06-15T14:13:44+00:00

I have a log file in AIX environment which has lines like below 10.100.108.23

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I have a log file in AIX environment which has lines like below

10.100.108.23 100.10.10.11 - [05/Dec/2012:09:35:27 +0000] "GET /chgs/checkprofile/checkServlet?requestType=signPart1&off=false&oquestions=true&userid=false&source=false&link=%23&country=us&language=en&origin=&displayLayer=no HTTP/1.1" 200 8904 "https://www.test.com/services/request/Home.action" "Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 6.1; WOW64; Trident/5.0; SLCC2; .NET CLR 2.0.50727; .NET CLR 3.5.30729; .NET CLR 3.0.30729; Media Center PC 6.0; .NET4.0C)" "PD-ERR=; rlang=nl_NL;

I need to find the country and language from each line which comes after the pattern &country and &language respectively. As i am new to shell scripting, i tried to achieve this with grep and awk scripts, but no luck.

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1 Answer

  1. Editorial Team
    awk -F"&" '{for(i=1;i<=NF;i++)if($i~/country/ ||$i~/language/){split($i,a,"=");printf a[2]" "}}' your_file

    Or you can use sed:

    sed -e 's/.*country=//g;s/language=\([^\&]*\)&.*/\1/g' your_file

    for removing that ampersand:

    > sed -e 's/.*country=//g;s/&language=\([^\&]*\)&.*/ \1/g' temp
us en

    you can read this

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