Question

I have a log file. The file is structured. Each line is delimeted by commas so that it looks like a table. I have to read from this file and transport the content to a database table. I want to treat the first 9 commas as delimeters and the rest ones as just a content of the tenth column. So, there can be more than 9 commas in a line but the tenth and the next ones shoudn’t be taken as a delimeter. I actually know how to do it by iterating through the characters and checking occurance of commas. But I don’t want it be inefficient. maybe there’s a better way? What would be the most accurate way to accomplish this? Either C# or Delphi is OK. For Oracle I’ll probably use Oracle but SQL Server is also an option.

Answer 1

The String.Split(char[],int) method overload achieves what you require. For example:

string line = "a,b,c,d,e,f,g,h,i,j,k,l,m,n";
string[] fields = line.Split(new char[] { ',' }, 10);

The fields array will contain ten elements. The first nine elements correspond the first nine substrings of line that were delimited by ',' characters, whilst the last element would correspond to the remaining substring (following the ninth ',' occurrence).

From MSDN (with count being the second argument passed to the Split(char[], int) method):

If there are more than count substrings in this instance, the first count minus 1 substrings are returned in the first count minus 1 elements of the return value, and the remaining characters in this instance are returned in the last element of the return value.

Thus, executing:

for (int i = 0; i < fields.Length; ++i)
    Console.WriteLine(string.Format("fields[{0}]: \"{1}\"", i, fields[i]));

would output:

fields[0]: "a"
fields[1]: "b"
fields[2]: "c"
fields[3]: "d"
fields[4]: "e"
fields[5]: "f"
fields[6]: "g"
fields[7]: "h"
fields[8]: "i"
fields[9]: "j,k,l,m,n"