Question

i have a logout link in jsp and i call the logout function like this

function logout(){
    document.getElementById("functiontype").value="logout";
    document.forms["frmTempcard"].submit();               
}

i call this like following : <li><a href="#" onclick="logout()">Logout</a></li>

when i click on the link i see the following url : http://localhost:8080/acct/notifier[the jsp file is there in this folder only ]/TempCardServlet

when i remove the folder name in url it is working fine. so how to redirect to desired servlet?

Please help me.

Answer 1

You should look at the action attribute of form, as per the code you have shared and the problem description, I feel you need to update action of your form.

Currently you would have given action='TempCardServlet' which means submit the request to TempCardServlet residing in the same URL as the current JSP page. This is relative path reference.

When you specify action='SomePath' then browser submits request to http://server/currenturl/SomePath. If the path to which you need to submit the request is not in current path then you need to either specify relative path or absolute path in following manner:

Relative Path (in your case): action='../TempCardServlet' – this method is not recommended as relative path might break your application

Absolute Path with Application context: action='/acct/TempCardServlet' – this would refer to servlet on the same server, drawback of this is that you are hard-coding applicaiton context. To overcome this you can use Servlet API to get current application context and append it to your servlet path – you can also use standard tag libraries to get the context path appended.